// P1462 通往奥格瑞玛的道路。城市费二分，非负道路耗血用 Dijkstra。
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
int main() {
    ios::sync_with_stdio(false); cin.tie(nullptr);
    int n, m; ll b; if (!(cin >> n >> m >> b)) return 0;
    vector<int> fee(n + 1), values;
    for (int i = 1; i <= n; ++i) { cin >> fee[i]; values.push_back(fee[i]); }
    vector<vector<pair<int,ll>>> g(n + 1);
    for (int i = 0, u, v; i < m; ++i) {
        ll w; cin >> u >> v >> w;
        g[u].push_back({v,w}); g[v].push_back({u,w});
    }
    auto check = [&](int X) {
        if (fee[1] > X || fee[n] > X) return false;
        const ll INF = 1LL << 60;
        vector<ll> dist(n + 1, INF);
        priority_queue<pair<ll,int>, vector<pair<ll,int>>, greater<pair<ll,int>>> pq;
        dist[1] = 0; pq.push({0,1});
        while (!pq.empty()) {
            auto [du,u] = pq.top(); pq.pop();
            if (du != dist[u]) continue;
            for (auto [v,w] : g[u]) {
                if (fee[v] > X) continue;
                if (du + w < dist[v]) {
                    dist[v] = du + w; pq.push({dist[v],v});
                }
            }
        }
        return dist[n] <= b;
    };
    sort(values.begin(), values.end());
    values.erase(unique(values.begin(), values.end()), values.end());
    if (!check(values.back())) { cout << "AFK\n"; return 0; }
    int l = 0, r = (int)values.size() - 1;
    while (l < r) {
        int mid = l + (r-l)/2;
        if (check(values[mid])) r = mid; else l = mid + 1;
    }
    cout << values[l] << '\n';
}