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cpp-courseware/2.Course/2.深入浅出程序设计竞赛(提高篇)/最短路/C++源码/03b_postman.cpp
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// P1629 / 教材例 10-3:有向正权图,题目保证任意两点互相可达。
// 输入 n m,随后 m 行 u v w;顶点从 1 编号。
#include <iostream>
#include <vector>
#include <queue>
#include <utility>
#include <functional>
using namespace std;
using ll = long long;
using State = pair<ll, int>;
struct Edge { int to; ll w; };
vector<ll> dijkstra(const vector<vector<Edge>> &g, int s) {
const ll INF = (1LL << 60);
vector<ll> dis(g.size(), INF);
priority_queue<State, vector<State>, greater<State>> q;
dis[s] = 0; q.push({0, s});
while (!q.empty()) {
State cur = q.top(); q.pop();
ll d = cur.first; int u = cur.second;
if (d != dis[u]) continue;
for (const auto &e : g[u]) {
ll nd = d + e.w;
if (nd < dis[e.to]) {
dis[e.to] = nd;
q.push({nd, e.to});
}
}
}
return dis;
}
int main() {
ios::sync_with_stdio(false); cin.tie(nullptr);
int n, m;
if (!(cin >> n >> m)) return 0;
vector<vector<Edge>> g(n + 1), rg(n + 1);
for (int i = 0; i < m; ++i) {
int u, v; ll w; cin >> u >> v >> w;
g[u].push_back({v, w});
rg[v].push_back({u, w});
}
vector<ll> out = dijkstra(g, 1);
vector<ll> back = dijkstra(rg, 1);
ll ans = 0;
for (int i = 2; i <= n; ++i) ans += out[i] + back[i];
cout << ans << '\n';
}